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2400=4x^2/x
We move all terms to the left:
2400-(4x^2/x)=0
Domain of the equation: x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-4x^2/x+2400=0
We multiply all the terms by the denominator
-4x^2+2400*x=0
We add all the numbers together, and all the variables
-4x^2+2400x=0
a = -4; b = 2400; c = 0;
Δ = b2-4ac
Δ = 24002-4·(-4)·0
Δ = 5760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5760000}=2400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-2400}{2*-4}=\frac{-4800}{-8} =+600 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+2400}{2*-4}=\frac{0}{-8} =0 $
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